The gene frequency of a new antigen BBa is 0.8. What percentage of individuals is expected to be BBa BBb?

To determine the percentage of individuals expected to be BBa BBb when the gene frequency of the antigen BBa is given as 0.8, we can use the Hardy-Weinberg principle. According to this principle, in a population at equilibrium, the genotype frequencies can be predicted from the allele frequencies.

In this case, let the frequency of allele BBa (denoted as p) be 0.8, and the frequency of the second allele, which we can assume as b (denoted as q), will therefore be 0.2, since p + q must equal 1 (0.8 + 0.2 = 1).

The genotype frequencies can be calculated as follows:

1. The frequency of homozygous individuals, BBa BBa, is given by p², which equals (0.8)² = 0.64 or 64%.

2. The frequency of heterozygous individuals, BBa BBb, is given by 2pq, which equals 2 * (0.8 * 0.2) = 0.32 or 32%.

Thus, the expected percentage of individuals that would be BBa BBb is 32%. This aligns with the